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com.flexstor.common.data.ejb.search
Class AssetTree

java.lang.Objectcom.flexstor.common.util.FlexNode
com.flexstor.common.data.ejb.search.AssetTree
- All Implemented Interfaces:
- java.io.Serializable
- public class AssetTree
- extends com.flexstor.common.util.FlexNode
For a single disguise, this object is filled by the SearchResultRetrievalBean.getAssetsStructure() method with information about some assets in a tree-like structure. The root element of the tree contains the disguise id, the next level contains the element bucket and from there downwards are all assets in their hierarchical structure (primary parent, child, parent, child, etc).
| Field Summary | |
static int |
DISGUISE
Constant to denote a disguise node (the root node) |
private long |
lNodeId
For the root node, this will be the disguise id, for first-level nodes this will be the element id, for the rest, it will be the asset ids. |
private int |
nNodeRole
Defines the asset role for this node, only if this is an ASSET node; otherwise it will be set to -1. |
private int |
nNodeType
Defines whether this is a node representing the root node, an element or an asset. |
| Fields inherited from class com.flexstor.common.util.FlexNode |
|
| Constructor Summary | |
AssetTree(long lId,
int nType)
Constructor to create a DISGUISE, ELEMENT or ASSET node. |
|
| Method Summary | |
void |
addChild(com.flexstor.common.util.FlexNode n)
Adds a node as a child of this one. |
boolean |
equals(java.lang.Object o)
Determine whether this Object is semantically equal to another Object. |
long |
getId()
|
AssetTree |
getNode(long lId,
int nType)
Starting at root, parse the tree looking for a specific node, based on the record id and type pecified |
int |
getRole()
|
int |
getType()
|
int |
hashCode()
Get a value that represents this Object, as uniquely as possible within the confines of an int. |
boolean |
isAsset()
|
boolean |
isChildAsset()
|
boolean |
isDisguise()
|
boolean |
isElement()
|
boolean |
isParentAsset()
|
boolean |
isPrimaryAsset()
|
void |
setParent(com.flexstor.common.util.FlexNode n)
Sets a node as the parent of this one. |
void |
setRole(int nRole)
Set the role for an ASSET node; if this is not an ASSET node, the role will be set to -1 |
| Methods inherited from class com.flexstor.common.util.FlexNode |
dispose, getChildren, getChildrenCount, getChildrenFlattened, getParent, getRoot, hasChildren, removeAllChildren, removeChild |
| Methods inherited from class java.lang.Object |
clone, finalize, getClass, notify, notifyAll, toString, wait, wait, wait |
| Field Detail |
DISGUISE
public static final int DISGUISE
- Constant to denote a disguise node (the root node)
- See Also:
- Constant Field Values
lNodeId
private long lNodeId
- For the root node, this will be the disguise id, for first-level nodes
this will be the element id, for the rest, it will be the asset ids.
nNodeType
private int nNodeType
- Defines whether this is a node representing the root node, an element or
an asset. It uses the constants in com.flexstor.common.constants.
BucketConstantsI class for identifying an element and an asset, and
AssetTree.DISGUISE for the root level
nNodeRole
private int nNodeRole
- Defines the asset role for this node, only if this is an ASSET node; otherwise it will
be set to -1.
| Constructor Detail |
AssetTree
public AssetTree(long lId,
int nType)
- Constructor to create a DISGUISE, ELEMENT or ASSET node.
Attempting to create any other type of node will throw a runtime IllegalArgumentException
| Method Detail |
getId
public long getId()
getType
public int getType()
setRole
public void setRole(int nRole)
- Set the role for an ASSET node; if this is not an ASSET node, the role will be set to -1
getRole
public int getRole()
isDisguise
public boolean isDisguise()
isElement
public boolean isElement()
isAsset
public boolean isAsset()
isPrimaryAsset
public boolean isPrimaryAsset()
isChildAsset
public boolean isChildAsset()
isParentAsset
public boolean isParentAsset()
setParent
public void setParent(com.flexstor.common.util.FlexNode n)
- Sets a node as the parent of this one. If a parent was already set, this method will set a new
parent. The previous parent-child relationship will be removed.
Three basic rules will be checked prior to assigning a parent to the current node:
- If the current node is a DISGUISE, it cannot have a parent node.
- If the current node is an ELEMENT, the parent node must be a DISGUISE.
- If the current node is an ASSET, the parent node must be either an ELEMENT or another ASSET.
If any of the above rules is broken, a runtime IllegalArgumentException will be thrown indicating
so in the message.
addChild
public void addChild(com.flexstor.common.util.FlexNode n)
- Adds a node as a child of this one. Multiple children can be added to a node.
Three basic rules will be checked prior to assigning a parent to the current node:
- If the current node is a DISGUISE, the child node must be an ELEMENT.
- If the current node is an ELEMENT, the child node must be an ASSET. If the element
has a child already assigned to it, an IllegalArgumentException is thrown indicating
the operation is not possible.
- If the current node is an ASSET, the child node must be an ASSET.
If any of the above rules is broken, a runtime IllegalArgumentException will be thrown
indicating so in the message.
getNode
public AssetTree getNode(long lId, int nType)
- Starting at root, parse the tree looking for a specific node, based on the record id
and type pecified
equals
public boolean equals(java.lang.Object o)
- Description copied from class:
java.lang.Object - Determine whether this Object is semantically equal
to another Object.
There are some fairly strict requirements on this method which subclasses must follow:
- It must be transitive. If
a.equals(b)andb.equals(c), thena.equals(c)must be true as well. - It must be symmetric.
a.equals(b)andb.equals(a)must have the same value. - It must be reflexive.
a.equals(a)must always be true. - It must be consistent. Whichever value a.equals(b) returns on the first invocation must be the value returned on all later invocations.
a.equals(null)must be false.- It must be consistent with hashCode(). That is,
a.equals(b)must implya.hashCode() == b.hashCode(). The reverse is not true; two objects that are not equal may have the same hashcode, but that has the potential to harm hashing performance.
This is typically overridden to throw a java.lang.ClassCastException if the argument is not comparable to the class performing the comparison, but that is not a requirement. It is legal for
a.equals(b)to be true even thougha.getClass() != b.getClass(). Also, it is typical to never cause a java.lang.NullPointerException.In general, the Collections API (
java.util) use theequalsmethod rather than the==operator to compare objects. However, java.util.IdentityHashMap is an exception to this rule, for its own good reasons.The default implementation returns
this == o. - It must be transitive. If
hashCode
public int hashCode()
- Description copied from class:
java.lang.Object - Get a value that represents this Object, as uniquely as
possible within the confines of an int.
There are some requirements on this method which subclasses must follow:
- Semantic equality implies identical hashcodes. In other
words, if
a.equals(b)is true, thena.hashCode() == b.hashCode()must be as well. However, the reverse is not necessarily true, and two objects may have the same hashcode without being equal. - It must be consistent. Whichever value o.hashCode() returns on the first invocation must be the value returned on all later invocations as long as the object exists. Notice, however, that the result of hashCode may change between separate executions of a Virtual Machine, because it is not invoked on the same object.
Notice that since
hashCodeis used in java.util.Hashtable and other hashing classes, a poor implementation will degrade the performance of hashing (so don't blindly implement it as returning a constant!). Also, if calculating the hash is time-consuming, a class may consider caching the results.The default implementation returns
System.identityHashCode(this) - Semantic equality implies identical hashcodes. In other
words, if
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