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edu.emory.mathcs.util.net.inproc
Class InProcSocketAddress

java.lang.Objectjava.net.SocketAddress
edu.emory.mathcs.util.net.inproc.InProcSocketAddress
- All Implemented Interfaces:
- java.io.Serializable
- public class InProcSocketAddress
- extends java.net.SocketAddress
Represents an address of in-proc socket. Consists of a logical port number.
- Version:
- 1.0
| Field Summary | |
(package private) int |
port
|
| Fields inherited from class java.net.SocketAddress |
|
| Constructor Summary | |
InProcSocketAddress(int port)
Creates new inproc socket address representing specified logical port. |
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| Method Summary | |
boolean |
equals(java.lang.Object obj)
Determine whether this Object is semantically equal to another Object. |
int |
getPort()
Returns the logical port number represented by this inproc socket address. |
int |
hashCode()
Get a value that represents this Object, as uniquely as possible within the confines of an int. |
| Methods inherited from class java.lang.Object |
clone, finalize, getClass, notify, notifyAll, toString, wait, wait, wait |
| Field Detail |
port
final int port
| Constructor Detail |
InProcSocketAddress
public InProcSocketAddress(int port)
- Creates new inproc socket address representing specified logical port.
| Method Detail |
getPort
public int getPort()
- Returns the logical port number represented by this inproc socket
address.
hashCode
public int hashCode()
- Description copied from class:
java.lang.Object - Get a value that represents this Object, as uniquely as
possible within the confines of an int.
There are some requirements on this method which subclasses must follow:
- Semantic equality implies identical hashcodes. In other
words, if
a.equals(b)is true, thena.hashCode() == b.hashCode()must be as well. However, the reverse is not necessarily true, and two objects may have the same hashcode without being equal. - It must be consistent. Whichever value o.hashCode() returns on the first invocation must be the value returned on all later invocations as long as the object exists. Notice, however, that the result of hashCode may change between separate executions of a Virtual Machine, because it is not invoked on the same object.
Notice that since
hashCodeis used in java.util.Hashtable and other hashing classes, a poor implementation will degrade the performance of hashing (so don't blindly implement it as returning a constant!). Also, if calculating the hash is time-consuming, a class may consider caching the results.The default implementation returns
System.identityHashCode(this) - Semantic equality implies identical hashcodes. In other
words, if
equals
public boolean equals(java.lang.Object obj)
- Description copied from class:
java.lang.Object - Determine whether this Object is semantically equal
to another Object.
There are some fairly strict requirements on this method which subclasses must follow:
- It must be transitive. If
a.equals(b)andb.equals(c), thena.equals(c)must be true as well. - It must be symmetric.
a.equals(b)andb.equals(a)must have the same value. - It must be reflexive.
a.equals(a)must always be true. - It must be consistent. Whichever value a.equals(b) returns on the first invocation must be the value returned on all later invocations.
a.equals(null)must be false.- It must be consistent with hashCode(). That is,
a.equals(b)must implya.hashCode() == b.hashCode(). The reverse is not true; two objects that are not equal may have the same hashcode, but that has the potential to harm hashing performance.
This is typically overridden to throw a java.lang.ClassCastException if the argument is not comparable to the class performing the comparison, but that is not a requirement. It is legal for
a.equals(b)to be true even thougha.getClass() != b.getClass(). Also, it is typical to never cause a java.lang.NullPointerException.In general, the Collections API (
java.util) use theequalsmethod rather than the==operator to compare objects. However, java.util.IdentityHashMap is an exception to this rule, for its own good reasons.The default implementation returns
this == o. - It must be transitive. If
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