interface. Array
deques have no capacity restrictions; they grow as necessary to support
usage. They are not thread-safe; in the absence of external
synchronization, they do not support concurrent access by multiple threads.
Null elements are prohibited. This class is likely to be faster than
Note that the fail-fast behavior of an iterator cannot be guaranteed
as it is, generally speaking, impossible to make any hard guarantees in the
presence of unsynchronized concurrent modification. Fail-fast iterators
throw ConcurrentModificationException on a best-effort basis.
Therefore, it would be wrong to write a program that depended on this
exception for its correctness: the fail-fast behavior of iterators
should be used only to detect bugs.
| Method from java.util.ArrayDeque Detail: |
public boolean add(E e) {
addLast(e);
return true;
}
|
public void addFirst(E e) {
if (e == null)
throw new NullPointerException();
elements[head = (head - 1) & (elements.length - 1)] = e;
if (head == tail)
doubleCapacity();
}
Inserts the specified element at the front of this deque. |
public void addLast(E e) {
if (e == null)
throw new NullPointerException();
elements[tail] = e;
if ( (tail = (tail + 1) & (elements.length - 1)) == head)
doubleCapacity();
}
|
public void clear() {
int h = head;
int t = tail;
if (h != t) { // clear all cells
head = tail = 0;
int i = h;
int mask = elements.length - 1;
do {
elements[i] = null;
i = (i + 1) & mask;
} while (i != t);
}
}
Removes all of the elements from this deque.
The deque will be empty after this call returns. |
public ArrayDeque clone() {
try {
ArrayDeque< E > result = (ArrayDeque< E >) super.clone();
result.elements = Arrays.copyOf(elements, elements.length);
return result;
} catch (CloneNotSupportedException e) {
throw new AssertionError();
}
}
Returns a copy of this deque. |
public boolean contains(Object o) {
if (o == null)
return false;
int mask = elements.length - 1;
int i = head;
E x;
while ( (x = elements[i]) != null) {
if (o.equals(x))
return true;
i = (i + 1) & mask;
}
return false;
}
Returns true if this deque contains the specified element.
More formally, returns true if and only if this deque contains
at least one element e such that o.equals(e). |
public Iterator descendingIterator() {
return new DescendingIterator();
}
|
public E element() {
return getFirst();
}
|
public E getFirst() {
E x = elements[head];
if (x == null)
throw new NoSuchElementException();
return x;
}
|
public E getLast() {
E x = elements[(tail - 1) & (elements.length - 1)];
if (x == null)
throw new NoSuchElementException();
return x;
}
|
public boolean isEmpty() {
return head == tail;
}
Returns true if this deque contains no elements. |
public Iterator iterator() {
return new DeqIterator();
}
Returns an iterator over the elements in this deque. The elements
will be ordered from first (head) to last (tail). This is the same
order that elements would be dequeued (via successive calls to
#remove or popped (via successive calls to #pop ). |
public boolean offer(E e) {
return offerLast(e);
}
|
public boolean offerFirst(E e) {
addFirst(e);
return true;
}
Inserts the specified element at the front of this deque. |
public boolean offerLast(E e) {
addLast(e);
return true;
}
Inserts the specified element at the end of this deque. |
public E peek() {
return peekFirst();
}
|
public E peekFirst() {
return elements[head]; // elements[head] is null if deque empty
}
|
public E peekLast() {
return elements[(tail - 1) & (elements.length - 1)];
}
|
public E poll() {
return pollFirst();
}
|
public E pollFirst() {
int h = head;
E result = elements[h]; // Element is null if deque empty
if (result == null)
return null;
elements[h] = null; // Must null out slot
head = (h + 1) & (elements.length - 1);
return result;
}
|
public E pollLast() {
int t = (tail - 1) & (elements.length - 1);
E result = elements[t];
if (result == null)
return null;
elements[t] = null;
tail = t;
return result;
}
|
public E pop() {
return removeFirst();
}
|
public void push(E e) {
addFirst(e);
}
|
public E remove() {
return removeFirst();
}
|
public boolean remove(Object o) {
return removeFirstOccurrence(o);
}
|
public E removeFirst() {
E x = pollFirst();
if (x == null)
throw new NoSuchElementException();
return x;
}
|
public boolean removeFirstOccurrence(Object o) {
if (o == null)
return false;
int mask = elements.length - 1;
int i = head;
E x;
while ( (x = elements[i]) != null) {
if (o.equals(x)) {
delete(i);
return true;
}
i = (i + 1) & mask;
}
return false;
}
Removes the first occurrence of the specified element in this
deque (when traversing the deque from head to tail).
If the deque does not contain the element, it is unchanged.
More formally, removes the first element e such that
o.equals(e) (if such an element exists).
Returns true if this deque contained the specified element
(or equivalently, if this deque changed as a result of the call). |
public E removeLast() {
E x = pollLast();
if (x == null)
throw new NoSuchElementException();
return x;
}
|
public boolean removeLastOccurrence(Object o) {
if (o == null)
return false;
int mask = elements.length - 1;
int i = (tail - 1) & mask;
E x;
while ( (x = elements[i]) != null) {
if (o.equals(x)) {
delete(i);
return true;
}
i = (i - 1) & mask;
}
return false;
}
Removes the last occurrence of the specified element in this
deque (when traversing the deque from head to tail).
If the deque does not contain the element, it is unchanged.
More formally, removes the last element e such that
o.equals(e) (if such an element exists).
Returns true if this deque contained the specified element
(or equivalently, if this deque changed as a result of the call). |
public int size() {
return (tail - head) & (elements.length - 1);
}
Returns the number of elements in this deque. |
public Object[] toArray() {
return copyElements(new Object[size()]);
}
Returns an array containing all of the elements in this deque
in proper sequence (from first to last element).
The returned array will be "safe" in that no references to it are
maintained by this deque. (In other words, this method must allocate
a new array). The caller is thus free to modify the returned array.
This method acts as bridge between array-based and collection-based
APIs. |
public T[] toArray(T[] a) {
int size = size();
if (a.length < size)
a = (T[])java.lang.reflect.Array.newInstance(
a.getClass().getComponentType(), size);
copyElements(a);
if (a.length > size)
a[size] = null;
return a;
}
Returns an array containing all of the elements in this deque in
proper sequence (from first to last element); the runtime type of the
returned array is that of the specified array. If the deque fits in
the specified array, it is returned therein. Otherwise, a new array
is allocated with the runtime type of the specified array and the
size of this deque.
If this deque fits in the specified array with room to spare
(i.e., the array has more elements than this deque), the element in
the array immediately following the end of the deque is set to
null.
Like the #toArray() method, this method acts as bridge between
array-based and collection-based APIs. Further, this method allows
precise control over the runtime type of the output array, and may,
under certain circumstances, be used to save allocation costs.
Suppose x is a deque known to contain only strings.
The following code can be used to dump the deque into a newly
allocated array of String:
String[] y = x.toArray(new String[0]);
Note that toArray(new Object[0]) is identical in function to
toArray(). |